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People also ask dimensional analysis and the crash of flight 143 worksheet answer key
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What is the volume of fuel needed for a flight if jet fuel has a density of 0.803 kg L?
We can rearrange the equation as follows: Volume = Mass/Density Substituting the given values in the above equation, we get: Volume = 23,800 kg / 0.803 kg/L Volume = 29,636.5 L (rounded to one decimal place) Therefore, the volume of fuel needed for the flight is approximately 29,636.5 L.
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How do you calculate the volume of fuel needed for a flight?
To calculate the volume of fuel needed for a flight, convert liters to kilograms using dimensional analysis and then divide the mass by the density to get the volume in liters.
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What is the specific volume of jet fuel?
Question: The specific volume of a certain type of jet fuel is 1.227×10−3 m3/kg.
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What is the density of a certain type of jet fuel is 775 kg m3?
The formula is Specific weight = density of fluid x acceleration due to gravity This gives: Specific weight = 775 kg/m³ x 9.81 m/s² = 7601.75 N/m³ (since 1N = 1kg. m/s²) Therefore, the specific weight of the jet fuel is 7601.75 N/m³.
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How did the calculation error affect the amount of fuel that was pumped into the plane?
The calculation error occurred when the ground crew measured the fuel in pounds instead of kilograms, the standard measurement unit for fuel in the airline industry. The plane, therefore, had signNowly less fuel than required for the flight, leading to its crash.
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What is the density of jet fuel in kg L?
Typical physical properties for Jet A and Jet A-1 Jet A-1Jet A Density at 15 °C (59 °F) 0.804 kg/L (6.71 lb/US gal) 0.820 kg/L (6.84 lb/US gal) Specific energy 43.15 MJ/kg (11.99 kWh/kg) 43.02 MJ/kg (11.95 kWh/kg) Energy density 34.7 MJ/L (9.6 kWh/L) 35.3 MJ/L (9.8 kWh/L)4 more rows
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What are the three possible causes of the 767 fuel pump alarm?
In the article, the "Crash of Flight 143," the fuel pump alarm of 767 was most likely caused by the failure of the pump, the clogging of the fuel line, and the running dry of the left tank.
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What units were needed on the number 1.77 to express the density of jet fuel?
The "conversion factor" of 1.77 was actually the fuel's density in pounds per liter, not kilograms. The fuel's density in kilograms per liter is 0.803.
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