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Lesson 8 1 Solving Systems of Linear Equations by Graphing Answer Key Form

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Instructions and help about solving systems of linear equations by graphing lesson 8 1

in this lesson we're going to solve a system of equations by graphing so the first equation is y is equal to 2x minus 3 and the second one is negative 2 over 3x plus 5 so what you want to do is you want to graph the two equations and you want to find out where the point of intersection is that's gonna be the solution but let's put some marks on the graph first let's go up to 5 on the y-axis let's do the same for the x-axis the advantage of drawing a big graph is you can clearly see what the solutions can be if you draw a graph with the marks closely spaced to each other it might be difficult to see the answer so the big of the graph the bet is going to be now each of these equations is in slope-intercept form so starting with the first equation we can see that M the slope is 2 and the y intercept is negative 3 so we need to go down at least three units so for the first equation the y-intercept is negative 3 that's gonna be the first point to find an exponent use the slope the slope is

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