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People also ask
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What is the minimum depth of a binary tree coding ninja?
Output: 2 The shortest path is from root node 1 to leaf node 2 which contains 2 nodes in the path. Hence, the minimum depth is 2.
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What is the height of a binary tree at least?
Theorem: a binary tree with n leaves has height at least log(n) . We have already noted in the lemma that the tree consisting of just the root node has one leaf and height zero, so the claim is true in that case. For trees with more nodes, the proof is by contradiction. Let n = 2^a + b where 0 < b <= 2^a .
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What is the minimum height of the tree?
What is a minimum height tree? Minimum height tree is rooted at the mid point of the longest path in the tree. The root of minimum height tree is the middle point of the longest path in the tree; hence there are at most two minimum height tree roots. Remember a tree has n nodes and n-1 edges.
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What is the minimum depth of the binary tree?
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. For example, minimum depth of below Binary Tree is 2. Note that the path must end on a leaf node. For example, the minimum depth of below Binary Tree is also 2.
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What is the formula for tree height?
Calculating tree height requires the use of basic trigonometry: h = Tan A x d, where h is the tree height, d is the distance from tree, and A is the angle to the top of the tree.
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How many bits are needed to uniquely identify any currently living human?
How many bits are needed: a. To uniquely identify any currently living human? (the notation dxe means the “ceiling” of x which is the least integer larger than x)k. Since 233 = 8, 589, 934, 592, 33 bits should be enough to uniquely identify every living person for at least the next decade.
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What is the formula for the minimum height of a binary tree?
If you have N elements, the minimum height of a binary tree will be log2(N)+1.
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What is the formula for calculating the height of a binary tree?
Compute the maximum of the heights of the left and right subtrees and add 1 to it for the current node. height = max(height of left subtree, height of right subtree) + 1.
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