
What is the Molality of a Solution Made from 2 4 Moles of Nacl and 0 80 Kg of Water Form


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People also ask
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How many moles of NaCl are there in 2 L of a 2 M solution?
Explanation: A 2M (2 molar) solution of NaCl means that there are 2 moles of sodium chloride (NaCl) dissolved in one liter (1 L) of the solution. This is a measure of the concentration of NaCl in the solution. So, in a 2M solution of NaCl, there are 2 moles of NaCl per liter of solution.
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What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water?
The molality of a solution is defined as the number of moles of solute dissolved in one kilogram of solvent. To find the molality of the solution, we need to divide the number of moles of solute (4 mol KCI) by the mass of the solvent (0.800 kg water). Molality = 4 mol / 0.800 kg = 5 mol/kg.
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What is the molarity of a 2.0 L solution that contains 2.4 mol of solute?
Molarity (M) = Moles of Solute / Volume of Solution (in liters) Molarity = 2.4 moles / 2.0 L Molarity = 1.2 M Therefore, the molarity of the solution made from 2.4 moles of NaCl and water in a 2.0 L volume is 1.2 M.
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What is the molarity of a 2.00 L solution containing 4.5 moles of NaCl?
The molarity of a 2.00 L solution containing 4.5 moles of NaCl is calculated by dividing the moles of NaCl by the volume of the solution in liters, resulting in a molarity of 2.25 M. This means that the solution has a molarity of 2.25 mol/L, which can be simply stated as 2.25 M.
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What is the molality of a solution prepared from 25.0 g NaCl and 100.0 g H2O?
The molality of a solution prepared from 25.0 g NaCl and 100.0 g H₂O is 4.28 m. This is found by converting the mass of NaCl to moles, the mass of H₂O to kilograms, and substituting these into the molality formula.
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What is the molarity of a solution in which 2.0 moles of NaCl have been dissolved in 0.5 liters of water?
4 M is the concentration of a solution if 2.0 moles of sodium chloride is dissolved in 0.50 liter of water.
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What is the molarity of 2.0 l of solution made from 2.4 moles of NaCl and water?
Molarity (M) = Moles of Solute / Volume of Solution (in liters) Molarity = 2.4 moles / 2.0 L Molarity = 1.2 M Therefore, the molarity of the solution made from 2.4 moles of NaCl and water in a 2.0 L volume is 1.2 M.
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How do you calculate the molality of the NaCl solution?
So: moles of NaCl = 70.128 g / (58.44 g/mol) = 1.2 mol . Plug the number of moles and the mass of the solvent into the molality formula. Divide 1.2 mol by 1.5 kg, and you'll find out that the molality of the NaCl solution is 0.8 molal (in standard molality units: 0.8 mol/kg).
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