Empirical and Molecular Formula Practice Worksheet
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People also ask questions on empirical formula and molecular formula with answers pdf
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How do you solve empirical and molecular formulas?
STEP 1: Calculate the molar mass of the empirical formula. STEP 2: Divide the given molecular molar mass by the molar mass calculated for the empirical formula. STEP 3: Multiply each subscript by the whole number that resulted from step 2. This is now the molecular formula.
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What is the empirical formula for trichloroisocyanuric acid the active ingredient in many household bleaches is O CNCL?
The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches, is OCNCl. The molar mass of this compound is 232.41g/mol.
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What is the empirical formula of a compound containing 92.3% carbon and 7.7% hydrogen by mass?
The compound's empirical formula is CH, while its molecular formula is C₆H₆, hence the correct answer is c) C₆H₆. Therefore, the compound's empirical formula is CH, and its molecular formula is C₆H₆ based on the given molar mass, therefore the correct answer is C₆H₆.
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What is the empirical formula of this compound containing 53 Al and 47 O by mass?
Solution: Convert the quantities to grams rather than percentages. Assuming a sample weight of 100 g, there would be 53 g of Aℓ and 47 g of O. 3 , we need to multiply by 2. aluminum : oxygen = 1 : 1.5 = 2 : 3 So the empirical formula is Aℓ2O3.
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What is the empirical formula of a compound that contains 28.8 g carbon and 2.42 g hydrogen?
Thus, 28.8 g of carbon represents 28.8/12 = 2.4 moles of carbon (C) and 2.42g of hydrogen represents 2.42/1 = 2.42 moles of hydrogen (H). The ratio of C:H is therefore 2.4:2.42, which simplifies roughly to 1:1. Hence, the empirical formula of this compound would be CH, option D in your question.
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What is the empirical formula and molecular mass of a compound are ch2o and 180g respectively?
=C6H12O6.
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What is the empirical formula of a compound that contains 0.783 carbon and 0.196 hydrogen and 0.521 g of oxygen?
Final answer: The empirical formula of a compound containing 0.783g of C, 0.196g of H, and 0.521g of O is CH3O, as determined by converting the element masses to moles and finding the ratio.
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What is the empirical formula of a compound that contains 0.783 g of carbon, 0.196 of hydrogen, and 0.521 of oxygen?
Final answer: The empirical formula of a compound containing 0.783g of C, 0.196g of H, and 0.521g of O is CH3O, as determined by converting the element masses to moles and finding the ratio.
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