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People also ask
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What is the empirical formula for 47.9% Zn 52.1% CL?
In this case, the empirical formula of the compound with 47.9% zinc and 52.1% chlorine is ZnCl2.
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What is the percent composition of a carbon-oxygen compound?
0:38 1:53 So for co2. If we add up the atomic mass for the carbon. And the two oxygens we'll get a molar mass.MoreSo for co2. If we add up the atomic mass for the carbon. And the two oxygens we'll get a molar mass. Of 44.01 grams per mole. So let's put the 44.01. On the bottom multiply by 100.
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What is the molecular formula of a compound that contains 30.45 percent nitrogen?
Final answer: To find the molecular formula of a compound with 30.45% nitrogen and 69.55% oxygen and a molar mass of 92.02 g/mol, first determine the empirical formula which is found to be NO2. Since the molar mass of the compound is twice that of the empirical formula mass (46.01 g/mol), the molecular formula is N2O4.
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What is the empirical formula for 52.2% C 13.0% H and 34.8% O?
The empirical formula of the compound is C2H6O.
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What is the empirical formula of 47.3 Cu and 52.7 Cl?
The empirical formula of a compound containing 47.3% Copper and 52.7% Chlorine is CuCl2. First, convert the weight percent into moles using the atomic masses of Copper and Chlorine. Then, find the simplest whole number ratio of elements in the compound.
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What is the empirical formula of a compound containing 47.9 potassium?
K =47.9% Be 5.5% F = 46.6%Empirical formula K2Be1F4 = K2BeF4.
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What is the empirical formula of Zn and Cl?
The empirical formula of zinc chloride is ZnCl2 . For zinc chloride, the empirical formula and the molecular formula are the same.
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What is the empirical formula of a compound containing 2.644 g of gold?
Given 2.644 g of gold and 0.476 g of chlorine, you can calculate the moles of gold and chlorine. Then, determine the simplest whole-number ratio between the moles of the two elements to find the empirical formula. In this case, the empirical formula would be AuCl3.
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