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hello this is matt dean with a plus college ready and today we're going to work some problems dealing with work power and energy start off with question one you lift straight up a four kilogram box to a height of two meters above the ground the box moves at a constant velocity for the entire displacement how much work did you do on the box key point is this term constant velocity that tells you that there's no net force acting on the object which means you're lifting so we'll call that your lift force we'll call it an applied force you're lifting with a force that's equal but opposite to the weight or the force of gravity so there's no net force acting on the box um the work done by you is going to be equal to force times distance times the cosine of theta where theta is the angle between the direction of the displacement and the direction of the force that's causing that work to happen well in this case the displacement is going to be straight up you're lifting straight up so the angl

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