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Of the point source is increased by a factor of three, what happens to the electric field strength? 4. What is the magnitude and direction of the electric field 0.25 meters away from a point charge with 5.0 µC. Draw a diagram. Use proportional reasoning to find the field strength at positions 0.125 meters away and 0.75 meters away. © Modeling Instruction - AMTA 2013 1 E1-Charge&Field - ws 5 v4.0 5. Sketch resultant vectors to represent the strength and direction of the electric field at...
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In this video we're going to focus on electric fields and how they effects positive and negative charges and also how to calculate the electric field created by a point charge the electric field is defined as the force exerted on a positive tinytest charge divided by the magnitude of the test charge now the units of electric field it's going to be the units of force which is Newton's divided by the unit of charge which is Kalume so typically electric field can be measured in Newton's per Coulomb is the force per unit charge now we know that the force between two charges according to Coulomb's law is K q1 q2 divided by R squared and if we take that force and divided by Q or one of the charges we get the equation for the electric field created by a point charge which is KQ divided by R squared now let's say if we have a positive charge what is the electric field produce by this positive charge at a distance of let's say 50 centimeters away now let's say the magnitude of the charge is 200

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