
Modulo Di Cessione Di Fabbricato E Di Dichiarazione Di Ospitalit Comune Minerbio Bo Form


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FAQs
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How much time does it take to get a yes/no answer for Canada Express Entry after filling out all the form & signing up? How many points are needed for a positive answer, i.e. how many points do the people that are getting accepted have on average?
The minimum that I know people got accepted is from 450 to 470 points.Usually when you fill up the information it tells you straight up if you are in the pool or not.By experience Canada’a express entry system is THE WORST THING EVER happened to the Canada’s immigration. It is literally a nightmare! The portal crashes, and sometimes only open between midnight and 3am. You literally need to be the luckiest person to have it work normally. What is worst about it: Is that the Canadian government keeps on saying they will fix issues, and in the same time calling it the best system ever, where it is the worst system I have ever seen. NO technical support whatsoever.Good luck in your application.My advice also, Canada is not as it advertises. It s quite hard out there, and people are racist (not to your face, but we a smile and in their mind, which is to the worst).I do not recommend Canada as a land for immigration, but I recommend Canada for studying. Schools there are pretty multicultural, and you do not feel the racism only when you go in the labour market or create your company.
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How does high-level high school football (e.g. California Open Division, Texas 6A-DI) compare to FCS, DII/DIII, and JUCO?
No matter where you are, always remember this. College football is a collection of good high school players. High school football is a collection of guys learning basic football. Just as the classroom teaches that no two children learn exactly the same way, the same holds true for high school football. In college, the expectations are that you can do it or the next guy will. In high school, the expectations are that you are taught to do it, and the better teams usually consist of guys who understand how to do their assigned duties.
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How is this equation [math]L\frac{di}{dt}+iR=E[/math] derived and is this equation suitable to use for solving an Ohm’s law problem?
it is simple KVL(kirchoff’s voltage law) equation of RL-series circuit fed with battery of voltage EE=voltage drop across R +voltage drop across LE=i.R+L[math]\frac{di}{dt}[/math]
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In Vietnamese (south), what is the difference between the letters "d" & "gi" in Viet when they both sound like the English letter "y"? I'm trying to get my voice-to-text to type out "dì" (aunt), but it keeps recognizing "gi" no matter how I say it.
The difference between ⟨d⟩ and ⟨gi⟩ is historical, and has been lost in all major dialects of Vietnamese. In northern Vietnamese, both are pronounced as /z/, and in southern Vietnamese both are pronounced as /j/ (like English ⟨y⟩).There might be some smaller dialects that still distinguish them, but that’s not the problem here. Because ⟨dì⟩ “aunt” and ⟨gì⟩ “what” are homophones, your voice-to-text can’t tell which you are trying to say unless you give it the right context—so when you say the word on its own it will just pick the most common one (which must be ⟨gì⟩).If you said a full sentence, the computer would be more likely to guess from the surrounding words which one you wanted to say—though I don’t speak Vietnamese and haven’t tried Vietnamese speech recognition, so I shouldn’t make any promises.
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How can I find the function of t? L (di/dt)+Ri=E, and how long will it take to signNow one half of its final value?
Interestingly, this seems to be the differential equation governing the behavior of an RL circuit. But this equation is separable, unlike most other circuit differential equations.[math]\frac{dI}{dt} = \frac{E - RI}{L}[/math].[math]L\frac{\frac{dI}{dt}}{E - RI} = 1[/math].[math]-\frac{L}{R} \ln (E - RI) = t + C[/math].[math]\ln (E - RI) = -\frac{Rt}{L} + C_{1}[/math].[math]E - RI = C_{2}e^{-\frac{R}{L}t}[/math].[math]I = \frac{E}{R} - C_{3}e^{-\frac{R}{L}t}[/math].If we assume we’re modeling an RL circuit, at [math]t = 0[/math] the current should be zero, because reasons (inductors are modeled as open circuits at time 0).So [math]C_{3} = \frac{E}{R}[/math]. Therefore [math]I = \frac{E}{R}(1 - e^{-\frac{R}{L}t})[/math].So we’re looking for when [math]e^{-\frac{R}{L}t} = 0.5[/math]. That’s when [math]t = -\frac{R}{L}\ln 0.5 = \frac{R}{L}\ln 2[/math].
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