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Degreeworks Technical Guide 2013-2025 Form
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FAQs
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If a company I worked for 3-4 years ago didn't reimburse me for few thousand dollars because I didn't fill out the form correctly, is there anyway to get this money back?
Their lawyer > your lawyerTheir resources > yoursIf you can now afford a lawyer on this you probably earn enough where this amount is not so signNow to you. In the end it's just money, and there are far more valuable things in life than money such as time; which no amount of money can buy.
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If the relationship was not given, how do we methodically find out that (-2,3) is rotated by clockwise 90 degrees about (1,1) to achieve (3,4)?
This is basic linear algebra (or complex plane geometry, for 2dimension figures there is no difference except the notation)Here you are given the centre of rotation, one initial point , the corresponding final point and the fact that it’s a 90 degrees rotation.You could remove knowlege of ONE of those things and find it using the others, but you cannot remove more than thatBasically let’s call A = [math]\pmatrix{-2\\3}[/math]the start point, A’=[math]\pmatrix{3\\4}[/math] the final point , C=[math]\pmatrix{1\\1}[/math] the center of rotation and R=[math]\pmatrix{0&-1\\1&0}[/math] the matrix of the rotation.the relation is simple A’-C= R (A-C)You can find R and C if you have more points and their image to work with, though you will not always get a rotation (rotation matrices on a plane are always like this [math]\pmatrix{\cos(\theta)&-\sin(\theta)\\\sin(\theta)&\cos(\theta)}[/math]
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How do I work out the cross product and dot product of vectors a (4,3) and b (-2,1)? The angle between these vectors is 30 degrees. I know the formula is magnitude of A*mag of b cos 30 for dot. And magnitude of a *magnitude of b sin 30 for cross.
For two 2-D vectors a and b, a = [a1, a2] and b = [b1, b2], the dot product (scale multiplication of vectors) is simply:a · b = a1 b1 + a2 b2Note that this will be commutative, so the order of the vectors doesn’t matter. So for the vectors a = [4, 3] and b = [–2, 1], the dot product will be:a · b = (4 x –2) + (3 x 1) = –8 + 3 = –5The angle between the vectors, y, can be calculated because:a · b = |a| |b| cos y and so cos y = a · b / (|a| |b|)In this case:cos y = –5 / (sqrt(4^2 + 3^2) x sqrt(–2^2 + 1^2)) = –5/ (5 x sqrt(5)) = –1/sqrt(5) = 0.447214So y = 63.434949°This isn’t 30°. You can check this mentally, because a is about 36.869898° from the x axis heading up and to the right, while b is about 26.565051° from the negative x axis, heading up and to the left. The angle y is between –a and b, the smaller angle between the vectors, and is about 36.869898° + 26.565051° = 63.434949°.Cross-products cannot be taken in 2-D space. They ONLY work in 3-D space (and 7-D, as I recall from a passing comment years ago). So you would need to convert them to 3-D vectors if you wanted to do this, but that isn’t in the scope of the question. It may be a trick to get you to do something that would show you haven’t studied the theory.For a 3-D cross-product, the result is actually a vector that is oriented at right angle to the plane formed by the two input vectors, i.e., the normal vector. Which normal vector (‘up’ or ‘down’) depends on the order in which the vector are considered, so vector multiplication is not commutative.If you were to take the chance in this problem and convert the vectors to 3-D, you would have a = [4, 3, 0] and b = [–2, 1, 0]. The vector product (cross-product) would then be:a x b = |a| |b| sin y nwhere n is the appropriate normal unit vector.In this case, you will geta x b = 5 sqrt(5) sin (63.434949°) na x b = 10 nNow all we need is the sense of n, which will be either coming out of the page towards you or going into the page away from you, assuming you have drawn the vectors on a piece of paper. Turning from a to b is counter-clockwise (anti-clockwise) and following the right-hand screw rule, the vector n will be coming out of the page towards you. If you assume that this is the positive third axis, then the scalar value with be +10 and the resulting vector will be:a x b = [0, 0, 10]As the answer (the cross-product) is exactly 10 n, we can expect that it was set up this way. Similarly, the fact that the dot product was exactly –5 suggests that this was the desired answer.Take a close look at where you got the 30° angle between the vectors. It doesn’t look right.
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If a car is travelling at 45mph, how long does it take to travel 3 1/4 miles? How is this worked out? I struggle to understand speed, distance, time, and calculations, and I soon have to sit the OASC.
A common problem people have with math questions is the lack of understanding that a verbal or written “Statement” has a direct translation into a math equation. The written statement says 45 mph. This is expanded to 45 miles per hour. Whenever “per” is written it’s direct translation is “divided by”. So the statement rewritten is 45 miles divided by 1 hour. This is written as 45 m/hr. So the solution is 45 m/one hr=3 1/4 m/(x) hr. You can substitute equivalent quantities to aid in your solution if necessary. Such as 60 minutes for 1 hour or 3.25 miles for 3 1/4 miles. You must be able to solve a math problem otherwise understanding the problem won’t help you. If you can’t rearrange the equation to come up with x on one side and the rest of the problem on the other you need a math tutor, not someone to explain the meanings of the terms. Get a tutor that can teach you the math terms for equivalent English terms. This inability to write an equation from an English question is the biggest obstacle for most people struggling with math. Unfortunately this is how almost every math question you ever get for the rest of your life is going to be formed.
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How can I motivate myself to work out 3 hours, study programming 4 hours and work 6 hours each day? I lose so much time on social networks and other stupid things. I’m not able to focus more than 1 hour on the same thing.
Let's do some math:3 (workout) + 4(programming) + 6(work) + 8(sleep) + 2(meals)+1(bathroom)=24 hours, not to mention you need time to get to work, return home, you need to cook your dinner, you need to have some time with your family. Surely you can spend less time eating your lunch, or cut time by sleeping 4-6 hours, but is it worth it. You should prioritise your time segments, if you are really ready to sleep less, or spend no time with your family, then it seems possible. Try to start with 1 hour of workout, 2 hours of programming, 6 hours of work, if after a while this schedule shows you can do more, then increase load bit by bit. After some time you will find balance that perfectly fits to you. As you said motivation is your problem here, every time you are starting something no matter workout, work, programming, just think about your perfect body in 6 months, think about promotion in a year, think about benefits it can give you in future.You need target to aim, if you have it, there will be a motivation. Divide big goal to a little and go to them one by one.
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A committee of five members is to be formed out of 5 IT officers, 4 clerks and 2 peons, In how many different ways can it be done if the committee should consists of 3 IT officers, 1 clerk & 1 peon?
5p3 ×4p1 × 2p1
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How do you solve a math question like this one, 1+2×3+4×5-6×7÷8? What is the correct order to work it out?
Step 1: Work out what country you’re in.Step 2: Work out which of the following the exam boards in your country use:BODMASBEDMASPEDMAS… some other… realise that they are subtly different, and the ‘correct answer’ is different in different countries.Step 3: Follow the rules in your country until your exam is overStep 4: Start working as a mathematiciansStep 5: Respond with horror to questions like the above because they don’t teach useful mathematical skills, and make young people believe that mathematics is somehow defined by arbitrary rules.
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People also ask
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What is the degreeworks technical guide?
The degreeworks technical guide is a comprehensive resource that provides in-depth information on the features and functionalities of the degreeWorks software. It offers step-by-step instructions to help users effectively implement and utilize the system for academic advising and degree audit processes.
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How does the degreeworks technical guide assist in integration with other systems?
The degreeworks technical guide includes detailed instructions on how to integrate degreeWorks with various institutional systems like student information systems (SIS) and learning management systems (LMS). This ensures seamless data flow and enhances the overall user experience while using the software.
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What are the key benefits outlined in the degreeworks technical guide?
According to the degreeworks technical guide, some key benefits include improved student success through efficient degree audits, streamlined academic advising processes, and enhanced reporting capabilities. These advantages ultimately lead to better educational outcomes and more effective use of resources.
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Is there a cost associated with accessing the degreeworks technical guide?
Typically, the degreeworks technical guide is provided as part of the degreeWorks software package, which may have associated costs. However, some institutions may offer access to the guide for free as part of their software subscription or purchase, making it essential to verify with your vendor.
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Can the degreeworks technical guide be used by non-technical users?
Yes, the degreeworks technical guide is designed to cater to users of all technical levels. It provides clear instructions and helpful visuals, making it easy for non-technical users to understand and utilize the functionalities of degreeWorks effectively.
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What features of degreeWorks are highlighted in the degreeworks technical guide?
The degreeworks technical guide highlights various features, including degree audits, program planning, course recommendations, and reporting functionalities. Each feature is detailed with practical examples to help users leverage them to enhance academic advising efforts.
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How can I contact support if I have questions regarding the degreeworks technical guide?
For any inquiries related to the degreeworks technical guide, users can typically signNow out via the support section outlined in their software package. It often includes email support, chat options, and access to a knowledge base for troubleshooting and further guidance.
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