Batch Condition Initials with airSlate SignNow

Batch subscribe initial

so let's do this documentary table for batch reactors I cut this diagram this is our batch reactor is being mix and as you can see there are no inlets no outlets everything is inside you got species a b c and d and why not some inert material it might be I don't know a nitrogen gas or maybe water that is not reacting anything that is inert but this is still there we are going to account it as inert and we have two things at the initial condition so time equals zero and at any time so n of a and a B and C and a B this means the amount at any time and na 0 NB 0 and C 0 is at time 0 so of course you are having reactions and of 0 will never be the same and of a at different times so we have this reaction suppose we have the reaction we're going to change it in terms of our limiting reactants so we will have 1 here and everything is divided by this coefficient a now just 2 may remind you we can relate the rate of reactions here ok let's use this table the initial amount of our moles the change that our that species is going to have and the final amount we're going to get after that conversion so for a is very easy because it's our limiting reactant and we are basing everything on a it's the initial amount of a ok the initial amount of VEC T I and total moles that's very easy the first column is the easiest one now the second one is the tricky one because we're going to calculate the change so what happens when you react or you have a conversion of a mouse well you need to multiply and this value here and of course is negative because you're losing amount let's do the same let's relate as you can relate here a and B we need to get this Tacoma trick value here and we still have an a serial times conversion of a this is the reactant and these two guys are products so that's why we got positive sign symbols here so TCG is the key metric relationship stoichiometric relationship because we are basing everything on a you call of course right X of C which will be kind of weird but we want to relate everything to a that's the point we are going to base everything on species a okay you're trusting me and yeah there's no change in a nerd my figure if you add all these you will get this is a common factor take it out and this is minus 1 minus B divided by a plus C divided by a plus D divided by a and if final value is essentially just the addition of this so NFA at any moment at any conversion is the initial amount plus the change and since it's being react the change will be negative so if this is here now let's do it for B initial amounts this number and the change is also negative because it's reacting and the same for C initial amount here and you're going to have a positive change because it's reacting and also for the initial amount and the change here many times we're going to have that we have no initial amounts of the products which makes sense because if you're making a reactor and maybe you are just pouring inside a and B well of course you have no initial amount of C and D and you can still have more of a let's say you have twice as in a what maybe 10 times more than a and still we are going to count it here and once again the initial amount of moles of inert material are the final amount of moles of and material just by definition they are not reacting so they don't have a change and they stay the same so if you want to add that you can add it with this value lost this value here please make sure you understand this table you have no idea sorry you have no idea what we're talking about is essentially look that this is the same the only thing that changes is of course this you can imagine a developer a negative because he's reacting B divided by a because he's reacting C divided by a because it's being produced and positive D divided by a because it being also produced okay and one thing here guys probably you saw this huge number in the book they call it this letter small D or rickety is like Delta but it's not the lowercase so they got this value they call it Delta so we're going to write it like this so you don't have to write everything and actually looks cool so the question is this equation right here is the actual change in moles due to the reaction let me show you an example for example a plus 2b if you see a is okay you have zero D okay you have Co T so that's why I wrote this over here one two one this C positive and you have two of B and you have 180 so you got this number what's the actual change of course you're at the beginning you've got three moles and at the end you've got one mole of course you're having a change of minus two moles you can do this the same here the same here the same here actually this is a nice case because you're going to have the same amount of module two moles in the left and two moles to the right and you can of course the difference is zero and don't forget always to divide these three so this will be actually a plus of C equals 2/3 of the don't forget that and yeah I recommend you to check out every one of these so you get good at calculating the amount of moles in changing due to reaction and let me bring this little table here don't forget it we are going to since we have it in malls and of a NOC n of T and I and total malls what will happen if I just divide by the volume of the reactor well if I divide by the volume of the reactor I'm going to get the concentration which is nice because I told you before we want to work with concentrations and not only concentrations we're going to work with concentrations based on a so let's do this we got this little number here is here divided by volume this little equation here just divided by volume this equation is also divided by volume and this equation here is also divided by body nice now in the book that they find this strange number here animals that's n be initial moles of B divided by the initial moles of a they call it this I don't know the Paris French number or viable I actually don't know the name of that Bible so I just say call it circled H or H Zuko okay now we got this from G we're going to be basing this here actually what we want to do is to relate these numbers and these numbers and these numbers once again to initial compression of a so let me do it here concentration of B I take this equation here once again I'm going to take this equation don't get lost guys this equation here I'm going to develop it so first thing first I want to do is take out an a zero so I take n of a zero divided by in a face here you can see this number is one so I got this the same value here guys I'm just multiplying by 1 which is n of a 0 divided by n of a 0 and what will happen if I pass this number inside I will get this value here and this one goes here also I got this number here and what I can coincidence we got our circle or H circle of be here so let's write that and I got these to be 1 so I got this equation and as you can see I related to initial amount of a and to this number here and conversion of a and psychrometric values here so as you can see I'm pretty much basing everything to a and I'm not going to do the same like the process I'm just going to show you how I will do it for C and D they get similar and of a of D the only thing that changes is of course this H circle of C and D circle no a trickle of T divided by volume sorry you and what else changes this is the geometric value and this is the geometric value conversion of a and the initial amount of a here still are the same so once again let me bring the new all the data if volume is constant I cut this here to beat this one here concentration this is concentration of a concentration of a concentration of a concentration of a this value here this value here and this value here and the psychrometric relationship stoichiometric relationship stake in metric relationship so this is what I want you to learn guys or at least not memorize but write it in your formulary this is what you want and this is only really valid when you got constant volume as you can see everything is expressed in terms of a you can see initial concentration of a in every equation you can see the conversion of a in every equation and you can see that all these two key metric values are based on a so we divided by a C divided by a D divided by a so that's what I wanted to get guys now those equations are valid only when the volume is constant why because you will see that for example I divided by volume and of a but what happens when the volume changes well we're going to have some problems but let me tell you when do we have constant value we have constant volume in liquid phase reactions and we have constant volume when we have isobaric use of chemical reactions of gases with no changes in moles so first things first this must be zero and you must have p1 equals p2 and t1 equals t2 so it's a very they get very not that common case but we have it but essentially don't get lost if we have liquid phase we can use this if we have gas phase don't go with it go with the assumption that you cannot use this equation and we're going to derive other equations that are valid for volumes or changing volumes when we don't have constant values so the equations we just got are not valid when you got gaseous phase reactions with changes bottoms so you have Delta any value that is not zero well you cannot use it if you have changing pressure you cannot use it you have change in temperature you cannot use it so essentially when it's a gas don't use it when you have liquids use it and this is a diagram I got from the book this here now this is our equation either you've got liquid phase or gas phase I told you when your liquid phase we watch the batch reactor we're going to see in the next video flow reaction reactors we got this here and because the volume is the same we can use these equations which are the ones we got hopefully you remember this is the reactions these are the equations we just got here let me go back this is here okay what else the special case for the gas phase and the batch so we were analyzing batch the gas phase and when you got constant volume you can use it so if you got constant volume you can use it that is not the case so we're going to see that you need to do all this stuff actually Larry it more we continue doing it so it's kind of complicated when you got gas phase look all these numbers also so the best case scenario is that liquid phase here and we're going to do this exercise in the next video what's up guys it's me Chemical Engineering guy so if you like the video right push the like button it really helps me to know if you like in the videos or if I should be changing something rather she'll be adding something taking out content we're also sharing is caring so if you got any kind of friends teachers colleagues or whatever kind of personally interested in this type of content one share it share helps our community to grow faster members and in content if you wanna keep track of my activity videos loop those experiments place what I wanted I'm getting you to be sure to click the subscribe button subscribing to the channel is totally free guys my dream is to create an online Academy of Chemical Engineering where everyone can access it in the world imagine a place in which the student the teacher and the engineer get the best of each father thank you thank you thank you guys from the sport hand it up