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Your step-by-step guide — verify being time
Using airSlate SignNow’s eSignature any business can speed up signature workflows and eSign in real-time, delivering a better experience to customers and employees. verify being time in a few simple steps. Our mobile-first apps make working on the go possible, even while offline! Sign documents from anywhere in the world and close deals faster.
Follow the step-by-step guide to verify being time:
- Log in to your airSlate SignNow account.
- Locate your document in your folders or upload a new one.
- Open the document and make edits using the Tools menu.
- Drag & drop fillable fields, add text and sign it.
- Add multiple signers using their emails and set the signing order.
- Specify which recipients will get an executed copy.
- Use Advanced Options to limit access to the record and set an expiration date.
- Click Save and Close when completed.
In addition, there are more advanced features available to verify being time. Add users to your shared workspace, view teams, and track collaboration. Millions of users across the US and Europe agree that a solution that brings everything together in a single holistic work area, is what businesses need to keep workflows functioning effortlessly. The airSlate SignNow REST API allows you to integrate eSignatures into your application, internet site, CRM or cloud storage. Check out airSlate SignNow and enjoy quicker, easier and overall more efficient eSignature workflows!
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How does signature verification work?
Verifying a signature will tell you if the signed data has changed or not. When a digital signature is verified, the signature is decrypted using the public key to produce the original hash value. The data that was signed is hashed. If the two hash values match, then the signature has been verified. -
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Log in to your account or register a new one. Upload a document and click Open in airSlate SignNow. Modify the document. Sign the PDF using the My Signature tool.
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Verify being time
number 72 verify that after a time of 10 milliseconds the current for the situation considered an example 23.9 will be 0.183 amps as stated so first if you read letter a here of example 23.9 it says it's asking us for the time constant all right uh when we have this 7.5 milli henry inductor and this resistor we know how to solve for the time constant now it's just the inductance divided by the resistance the time constants here will be the inductance 7.5 millihenry but you know we need that in henry so therefore we're going to multiply by 10 to the minus 3. the resistance there is 3 ohms we don't have to do anything to that and then what we're going to do is we're going to take out that calculator and we're going to start plugging some numbers in so 7.5 times 10 to the minus 3 divided by 3 and this works out to be about 2.5 times 10 to the now minus 3. all right uh seconds so one two three yeah so that is now the time constant now what we can do here is uh we can now use all right the uh basically the the decay formula here okay this is a type of exponential decay and where we can find now that the current at some future point in time will equal the initial current okay i sub o so i'm going to call it i sub i for initial multiplied by e raised to the negative t divided by tau so this is the time the circuit's on this is the time constant and this is the initial current so the initial current here uh it told us in the problem is 10 amps so plug that in then the time well how long it says verify that after a time of 10 milliseconds so we know that this is going to be 10 times 10 to the minus 3 then divided then by the time a constant right which we just found which is 2.5 times 10 to the minus 3. so these bases will cancel out and then you can take 10 and divide it by 2.5 and that works out to be about 4. don't forget the negative sign there as well all right so this is going to be now the current at some time in the future and basically 10 milliseconds is going to be equal to 10 raised or excuse me 10 multiplied by e raised to the negative fourth so simply take out now the calculator and do 10 multiplied by e raised to the negative fourth and we get a value of 0.183 amps wait a minute that's what the problem told us that's the point guys thanks for tuning in appreciate it hopefully that helps and uh check out some more videos if you're taking chemistry or pre-calculus uh concurrently or sometime in the future um or if...
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